Question

y=[ln(1+e^x)]^6

Answer 1

i know that u'/u
but im not sure how to make it work with this problem

Answer 2

what is the question? take the derivative ?

Answer 3

yes

Answer 4

if the problem were
y= u^6 you would do
dy = 6u^5 du

now replace u with ln(1+e^x)
let 1+e^x be v
you have u= ln(v)
du = d (ln(v))= 1/v dv

now if we replace u and v with the originals

dy= 6 (ln(1+e^x))^5 * 1/(1+e^x) d (1+e^x)
can you finish?

Answer 5

you use the chain rule, which might be confusing....

Answer 6

yes that helped a bunch