Question

Find the lateral area the regular pyramid. with a slant of 4in. and base sides are 4in

Answer 1

Pleas help

Answer 2

Is base a triangle?

Answer 3

no sorry lol

Answer 4

There are 4 triangle facets.
I think \[Area = 4 \times 4 \times 4 \times \sin60\]
\[Area = 32\sqrt{2}\]

Answer 5

Each triangle has an area \[8\sqrt{2}\]

Answer 6

was that the L.A. or T.A.?

Answer 7

ok

Answer 8

lateral area will be 4 times the area of triangle.

Answer 9

32 square root 8?

Answer 10

Silon?

Answer 11

oops sorry.\[\sin60 = \frac{ \sqrt{3} }{ 2 }\]
The area is \[32\sqrt{3}\]

Answer 12

OH ok so the L.A. is \[\sqrt[32]{3} \]

Answer 13

hehe, I mean \[32\times \sqrt{3}\]

Answer 14

ok? i am looking for an answer that looks like _ _ \[\sqrt{_}\]

Answer 15

sorry im new to this the answer should look like
_ _ sqr _

Answer 16

32 sqrt 3 ?

Answer 17

no that answer is only partially right

Answer 18

hello?

Answer 19

partially right?

Answer 20

yes i am doing the question online and it say it is only partially correct

Answer 21

Can you send me print screen pic as a attachment, so I can see?

Answer 22

https://media.glynlyon.com/g_geo_2012/8/groupi77.gif

Answer 23

did that help?

Answer 24

Got it, Actually, we have 3 facets. The base is a triangle. \[LA = 3 \times 4 \times 4 \sin60 = 24\sqrt{3}\]

Answer 25

awesome thank you SO MUCH. can you also find the T.A.?

Answer 26

What is TA?

Answer 27

triangle area?

Answer 28

Total Area

Answer 29

Sure, \[TA = 4 \times 4 \times 4 \sin60 = 32\sqrt{3}\]

Answer 30

You awesome. now if your up for it? can you find the volume?

Answer 31

hello?

Answer 32

oh no and i just submitted those answers and they are still partially correct.

Answer 33

Let me correct mistakes.each triangle has an area \[Area of \triangle = \frac{ 4\times4 \times \sin60 }{ 2 }\]

Answer 34

Area of triangle is 4 sqrt 3

Answer 35

\[LA = 3\times4\sqrt{3} =12\sqrt{3}\]

Answer 36

\[TA = 4\times 4\sqrt{3} = 16\sqrt{3}\]

Answer 37

\[The Volume =\frac{ 4^{3} }{ 6\sqrt{2} } = \frac{ 16\sqrt{2} }{ 3 }\]

Answer 38

Sorry that I made a stupid mistake :(

Answer 39

Hello?

Answer 40

hey sorry i thought you left.

Answer 41

All of those answers are correct thank you so much.

Answer 42

You are welcome :)