Question

Find y′ if xy=yx.

Answer 1

i got here before i got stuck
ylnx=xlny

Answer 2

the problem is suppost to be
x^y=y^x

Answer 3

\(\large x^y=y^x \)
\(\large lnx^y=lny^x \)
\(\large ylnx=xlny \)
\(\large [ylnx]'=[xlny]' \)
\(\large y'lnx+y\frac{1}{x}=x'lny+x\frac{y'}{y} \) product/chain rule

Answer 4

now isolate the y'....

Answer 5

thank you i didn't think to use the product rule