Expand completely: log
\[\log _{3}(x^{2}y^{3}) \over (_{z^4})\]
@jim_thompson5910 I don't have a clue
is everything in the log? or is it just the expression x^2y^3 only in the log?
everything is in the log
I couldn't figure out how to get the z^4 in the prenthesis
So the full problem is actually \[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\]
yes
I am having a hard time with these
first use the idea that log(A/B) = log(A) - log(B) \[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\] \[\Large \log_{3}\left(x^{2}y^{3}\right )-\log_{3}\left(z^{4} \right )\]
Then use the idea that log(AB) = log(A) + log(B) \[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\] \[\Large \log_{3}\left(x^{2}y^{3}\right )-\log_{3}\left(z^{4} \right )\] \[\Large \log_{3}\left(x^{2}\right )+\log_{3}\left(y^{3}\right )-\log_{3}\left(z^{4} \right )\]
ok let me see from here
why at one point we were subtracting and then it was switched to addition
I expanded \[\Large \log_{3}\left(x^{2}y^{3}\right )\] into \[\Large \log_{3}\left(x^{2}\right )+\log_{3}\left(y^{3}\right )\]
So that's where the addition came from (the subtraction is still there)
I'm just ignoring it for now
what happened to z^4
like I said, I'm ignoring it for now and only focusing on expanding \[\Large \log_{3}\left(x^{2}y^{3}\right )\]
to show where the addition came from
ok
so where do I go from here
ok let me retype all of the steps so far
\[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\] \[\Large \log_{3}\left(x^{2}y^{3}\right )-\log_{3}\left(z^{4} \right )\] \[\Large \log_{3}\left(x^{2}\right )+\log_{3}\left(y^{3}\right )-\log_{3}\left(z^{4} \right )\]
The last step is to pull down the exponents using the idea that log(x^y) = y*log(x)
So the full step by step answer is
\[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\] \[\Large \log_{3}\left(x^{2}y^{3}\right )-\log_{3}\left(z^{4} \right )\] \[\Large \log_{3}\left(x^{2}\right )+\log_{3}\left(y^{3}\right )-\log_{3}\left(z^{4} \right )\] \[\Large 2\log_{3}\left(x\right )+3\log_{3}\left(y\right )-4\log_{3}\left(z \right )\]
Which means that \[\Large \log_{3}\left(\frac{x^{2}y^{3}}{z^{4}} \right )\] fully expands out to \[\Large 2\log_{3}\left(x\right )+3\log_{3}\left(y\right )-4\log_{3}\left(z \right )\]
ok thank you @jim_thompson5910
yw
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