help? sinx+sqrt3(cosx)=-sqrt3
start by moving the -sqrt3 over to the left and the sinx over to the right. square both sides, then make a substitution sin^2 = 1-cos^2
hint: its gonna be messy. but i prefer to convert everything to just one trig function
Hmm will that work? When you square the left side (without moving the -sqrt3), you'll get a middle term 2sqrt3sinxcosx.. I'm not sure what you can do with that :( hmmm
you move the sin to the right and the sqrt 3 to the left. then if you factor out the sqrt3, it should work well, you end up with a quadratic in terms of cosine and no sines
hmmm...cant factor the quadratic tho..might have to use quadratic formula... this problem is really tough
|dw:1352083061663:dw| Hmmm yah that sounds like it might work :o Hopefully I did that correctly.
Join our real-time social learning platform and learn together with your friends!