Question

Which function has a removable discontinuity?

Answer 1

answer choices A,B,C,D from top to bottom :)

Answer 2

try factoring each of them and canceling terms

Answer 3

isn't there like another method?? and idk how does that solve the question to get the answer??

Answer 4

a removable discontinuity usually is removed by factoring the top and bottom, and removing common factors, which then will result in an equation with a domain larger than the previous equation.
so, no, theres no other way
just factor them (if they can be) and try to cancel stuff

Answer 5

can u pls show me?? I'm confused :(

Answer 6

if you factor the denominator in the second one, what do you get?

Answer 7

umm (x-2)(x+1) ??? is tha tright??

Answer 8

yes. notice you can cancel the (x-2) in the top and bottom, right?

Answer 9

uhuhhh so i get 1/x+1 ??

Answer 10

notice before how the function had 2 places where a divide by 0 occurs (x=2 and x=-1) now theres only 1 (at x=-1). you just removed a discontinuity. thats why its "removable"

Answer 11

mhmmm so my answer is B???

Answer 12

yup :)

Answer 13

the one with p(H) ?? is it ht done i attached?? is that the answer??

Answer 14

yup

Answer 15

awesome!! thanks :)

Answer 16

welcome :)

Answer 17

awesome!! thanks :)