prove that if A,B AND are three points in space,then the area of triangle ABC can be calculated with formula : Area of triangle ABC =1/2 absolute AB*AC.
uhm, that would be the cross-product of vectors AB and AC.
HOW
can we assume this? \[\huge \left| A \times B \right|=\left| A \right| \left| B \right| \sin \theta \]
YES
\[\large \left| AB \right|\]is the length of vector AB and \[\large \left| AC \right|\] is the lengthh of AC, while theta is the angle formed by the two vectors. the area of a side-angle-side triangle is \[\large \frac{ 1 }{ 2 } ab \sin \theta\]
\[\large \frac{ 1 }{ 2 }\left| AB \times AC \right|=\frac{ 1 }{ 2 }\left| AB \right|\left| AC \right| \sin \theta\] and the right side of the equation is the area of the triangle.
WHAT ABOUT IF YOU DONT ASSUME?
then we'll have to prove it.
CAN YOU DO IT?
most textbooks include a proof of \[\large \left| AB \times AC \right|=\left| AB \right|\ \left| AC \right| \sin \theta\] so i leave reading the proof to you.
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