Find the slope intercept equation of the line segment that passes through (1,3) and (3,-3)
first find the gradient between the 2 p0ints... then just substitute to general linear line equation...
I need help
ok... first u know right the formula how to find the gradient between 2 points...??? that is : \[m = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\] and then by substituting one of the coordinate of the p0int to the general linear line equation . that is \[y - y _{1}= m(x-x _{1})\] where your \[y _{1} and x _{1} \] is your coordinates that you want to substitute
@oheneba do you get it...???
ok
@Eda2012 so m= Y₂ -y₁/ X₂ -X₁ =-3
@oheneba yes...ok u got it right...
@Eda2012 where do I go from here?
then u substitute one of the coordinate of the point to the general formula...
where \[y-y _{1} = m(x-x _{1})\] your m = -3 your \[x _{1}\] and \[y_{1}\] is your coordinate of the point.
so y-3=-3(x-1)?
@Eda2012 so y-3=-3(x-1)?
yeah....thats right... now u just simplify your answer and you've done..
y=-3(x+2)
@Eda2012 y=-3(x+2)
y=-3x-6
@Eda2012 y=-3(x+2 y=-3x-6 ?
no... it suppose to be like this... \[y=-3(x+2)+3\] you cannot simply add or minus any number in the bracket....
sorry my mistakes the equation suppose to be like this \[y=-3(x-1)+3\]
but still you cannot simply add or minus any number in the bracket with the number that outside the bracket...
Thanks. So this will be the final answer, right?
no...you have to simply it...
And how do I do that?
-3x-3+3?
yes...but you did a careless mistake in your answer just know... it suppose to be -3x+3+3
-3x+3+3...lol.. Thanks =3x+6?
yes!!! welcome~
Join our real-time social learning platform and learn together with your friends!