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Mathematics 7 Online
OpenStudy (anonymous):

Find the critical points and the intervals on which f (x) = x^2-5x+6/ x^2? increases/decreases. Hence decide whether each critical point represents a minimum, a maximum or neither. ??

OpenStudy (anonymous):

Can you calculate the first derivative? Use quotient rule.

OpenStudy (anonymous):

yes done it all out and think it has one critical point at -0.0417 at local min but not sure am i right . i got 1st & 2nd derivative then got x =2.4 subed it back in nd got that answer but am not sure am i correct

OpenStudy (anonymous):

I got a critical point min at x = 2.4. I didn't bother with the second derivative and I just noticed that the first derivative goes from - to + at x = 2.4, so that one's for sure.

OpenStudy (anonymous):

Aslo, looks like the function increases for x<0 and x > 2.4. Decreases in 0 < x < 2.4

OpenStudy (anonymous):

yes i think it has 1 critical point which is a minimum but i was just trying to see was i right as was a bit unsure

OpenStudy (anonymous):

No, you're right. f(x) also goes to infinity on left and right-hand of x going to 0

OpenStudy (anonymous):

cheers

OpenStudy (anonymous):

Horizontal asymptote of f(x) at 1 for x going to infinity. You, too on the cheers! I'm right now drinking Octoberfest beer.

OpenStudy (anonymous):

So, just one relative min. No max.

OpenStudy (anonymous):

yes i think so , hopefully this is the right answer for my problem sheet !!!

OpenStudy (anonymous):

I graphed it and yes, it just has this one min. No max.

OpenStudy (radar):

@tcarroll010 are you in Germany?

OpenStudy (radar):

Octoberfest is big in Bavaria.

OpenStudy (anonymous):

No, I'm in the U.S. I'm just one of the few with good, European beer taste, lol. :-)

OpenStudy (radar):

Great, I am in U.S. also, but did spend 3 years in Bavaria near Bad Toelz,Germany. (Thanks to our U.S. Army)

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