f(x) = x + 1. Part 1: Find f(2). Part 2: Find x when f(x) = 2
Part 1: Plug in 2 for x in the equation So, f(2)= 2+1 f(2)=3
So, f = 1.5?
Part 2: Set your equation f(x) equal to 2 and solve. So, x+1=2 subtract 1 from the x to isolate x. x=1
lolwut?
What do you not understand?
So, f(2) =3 then that would come out to be f = 1.5?
You are not solving for f.
So thats the answer?
f is the function, not a variable you want to find.
@Guez, "f" is a function, not a multplier... for this problem, it's a rule that says, if you give me "x", I will give you back "x + 1"
so if @Brittni0605 gives you x = 2, then your function gives back 2 + 1 = 3
f(2)=3 and when f(x)= 2 your x value equals 1
So the answers are.. Part 1 : f(2) = 3 Part 2 : x = 1 ? I understand how to do the first one but not the second one.
Yes, correct
Part 2 is like the reverse... you know your function gave back "2" as an answer... what must you have provided as an input to get "2" back?
For the second part, the question is asking what x value will make 'x+1' = 2
so lets say for part 2 it would have said Find x when f(x) = 4. The answer would have been x = 4?
No, the answer would be 3
If it said find f(x)=4: x+1=4 x=4-1 x=3
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