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Solve for x: log^(5x+9)(x^(2)+6x+9) + log^(x+3) (5x^(2)+24x+27)=4
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\[\log_{5x+9}(x^{2}+6x+9)+\log_{x+3} (5x ^{2}+24x+27)=4 \]
Use the product rule to get log_bM+log_bN for the first half right? .....so that would be log(5x+9)+log(x^2) ... right? Im new at this
I think so i'm not sure
yeah cause if you simplify too soon it will be a mess lol
so i would set m=log(5x+9) n=log(x+3) for example?
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the (5x+9)(x^2) is being multiplied together right? just clarifying
ya
okay, neato! ... so, yes start with the product rule to |dw:1352156637852:dw|
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