Question

Pre Calc. Can anyone help me?

Answer 1

What's the question?

Answer 2

"Can anyone help me?"

Answer 3

YES! :D

Answer 4

\[f(x) = \frac{ 2 }{ x^2-2x-3 }=\frac{ 2 }{ (x+1)(x-3) }\]

Answer 5

okay

Answer 6

That means the x cannot be -1, 3
so the domain (-infi, -1)U(-1, 3)U(3, infi)

Answer 7

or x <-1, -1<x<3, x>3

Answer 8

okay

Answer 9

for x-intercept:
set f(x)=0, then:
\[0=\frac{ 2 }{ (x+1)(x-3) }\]
since no x exist that satisfy the above equation, there is no x-intercept

Answer 10

for y-intercept:
set x = 0, then:
\[f(0) = \frac{ 2 }{ (0+1)(0-3) }=\frac{ -2 }{ 3 }\]
so the y-intercept is at the point (0, -2/3)

Answer 11

To get the horizontal asymptote:
divide every individual block in the equation by the highest power of x, which is x^2

Answer 12

no x inct? no range?

Answer 13

o lol, forgot about range
and there's no x-int as I've explained

Answer 14

okay

Answer 15

sorry, I need to a lecture now, but here is the graph for reference. good luck :D

Answer 16

okay.

Answer 17

anyone?