Question

How do I solve this using identity:
cos^2x/(1+2sinx-3sin^2x) = (1+sinx)/(1+3sinx)

Answer 1

let sin (x) be b

Answer 2

i have to use trig identities tho^

Answer 3

(1+2sinx-3sin^2x)

1+2b-3 b^2
=
(1+3b)(1-b)

Answer 4

cos^2x

use identiry

sin^2(x)+cos^2(x)=1
cos^2=1-sin^2(x)---->1-b^2

1-b^2=(1+b)(1-b)

Answer 5

(1+b)(1-b)
--------------
(1+3b)(1-b)

(1-b) cancels

leaving
(1+b)
------------------
(1+3b)



remember b=sin(x)

1+

Answer 6

thanks

Answer 7

no problem