Question

write in logarithmic form
(2/3)^-1 = 3/2

Answer 1

on taking log both the sides you will get
\[\log ((2/3)^ {-1})=\log (3/2)\] which gives you\[-1*\log (2/3)=\log(3/2)\]

Answer 2

\[\log a -\log b= \log (a/b)\]

Answer 3

can you do the rest?

Answer 4

log (3/2) + log (2/3)
and Log a + log b = Log (a*b)

Answer 5

i think by "logarithmic form" they mean change
\[b^x=y\] to \[log_b(y)=x\]

Answer 6

so \((\frac{2}{3})^{-1}=\frac{3}{2}\) becomes
\[\log_{\frac{2}{3}}(\frac{3}{2})=-1\]

Answer 7

but what i have done, is also one of the possibilities

Answer 8

uh... i stuck with -log(2/3)=log(3/2)
because when i do evaluate that i get 1.

Answer 9

you will get zero
log a + log b = log (a*b)= log ( 2/3 * 3/2) = log 1 =0