Question

If f(x)=4(x^2)-4x+3 find f'(1). This equals 4, which I know. Then it says" Use this to find the equation of the tangent line to the parabola Y=4(x^2)-4x+3 at the point (1,3). The equation of this tangent line can be written in the form Y=mx+b where m is: (blank) and where b is: (blank)."

Answer 1

The slope of the tangent line is given by the first derivative. Can you take a derivative?

Answer 2

It's 8x-4, I used that to get the answer 4. Not sure where to go from there. I don't remember how to find the tangent line equation to the parabola.

Answer 3

so m=4 ; and b is your y intercept = 3.

Answer 4

y=4x+3

Answer 5

Your slope should be negative tho.

Answer 6

so y=-4x+3

Answer 7

8-4=-4 ---> you got it?

Answer 8

Both of those answers are incorrect

Answer 9

Nvm. -4 was incorrect. 4 is correct for m. But B is wrong.