if $$\log_{9}4=a$$and $$\log_{27}5=b$$ find an expression in terms of a & b for $$\log_{3}80$$

Question

if $$\log_{9}4=a$$and $$\log_{27}5=b$$  find an expression in terms of a & b for $$\log_{3}80$$

anonymous · Answer

i had that backwards 
$$2\log_9(4)=\log_3(4)$$ and 
$$3\log_{27}(5)=\log_3(5)$$ now lets see what we can do with $\log_3(80)$

anonymous · Answer

since $80=4^2\times 5$ we can write 
$$\log_3(80)=\log_3(4^2\times 5)=\log_3(4^2)+\log_3(5)=2\log_3(4)+\log_3(5)$$

anonymous · Answer

now substitute back for $a$ and $b$ and you will get your answer

anonymous · Answer

this is how they explained for me to do it...so im sort of just going by this.
lookin at what you did... im gettng a little lost... /: