Question

Set following equation up in partial fraction decomposition form:

Answer 1

\[\frac { 5{ x }^{ 2 }-2x+3 }{ ({ x }^{ 2 }+1)(x-1) } \]

Answer 2

\[5x^2-2x+3=\frac{ A }{ x^2+1 }+\frac{ B }{ x-1 }\]

Answer 3

I need to correct something

Answer 4

ya, just wanted to make sure this is the correct approach.
thx.

Answer 5

oh wait
it should be Ax+B there instead of A i think

Answer 6

The left should be the original equation, the right is correct. Did you understand that or would you like to see it?

Answer 7

ya i understand that

Answer 8

but i think you have to make the right \[\frac{Ax+B}{x^2+1}+\frac{B}{x-1}\]

Answer 9

I think you are right except the next fraction should be a "C"

Answer 10

In my notes I show that if you have (x^2 + c) you do what you did with Ax+B.
(x+c) is just an A. But I show no repeated letters.

Answer 11

yeah wow typo

Answer 12

getting late

Answer 13

thank you :)

Answer 14

\[\frac{ 5x^2-2x+3 }{ (x^2+1)(x-1) }=\frac{ Ax+B }{ x^2+1 }+\frac{ C }{ x-1 }\]

Answer 15

your welcome good luck