Describe the transformation from f(x)=a^x to f(x)=b^x where 1
graphs have same shape but slope is greater with the a^x (it increases at faster rate)
I was asking for more along the lines of vertical stretch, horizontal stretch, etc.
its a horizontal stretch, relatively to the parent. for example y = 2^x , y = .5 ^ x
by what factor?
a ^[ x * ln b / ln a ] = b^x
how did you get that?
look at easier examples, comparing y = 2^x and y = 2^(2x)
ok here is a general rule
you ready ?
if you start with f(x) , f (ax) does a horizontal stretch/shrink by a factor of 1/a. it depends on a, and we assume a > 0 . if 0<a<1, then its a horizontal stretch because if a < 1 then 1/a > 1 , and if a > 1 , then it is a horizontal shrink because 1/a < 1
so it becomes clear if its a stretch or a shrink because of the factor itself. if the factor is less than 1, then its a shrink. if its greater than 1 its a stretch
now we started with f(x) = a^x , then f ( ln b/ ln a * x ) = a ^ (ln b / ln a * x ) = b^x . so f(x) is stretched or shrinked by a factor of ln a / ln b (the reciprocal )
the important thing is that it is horizontal
you there ?
I understand the picture but I don't understand how that translated into lnb/lna
the 1st picture
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