Question

Determine if the given lines are parallel, perpendicular or neither: 3x + 4y = 6 and 4y = 3x + 7.

Answer 1

well if they're parallel they will have the same slope, and a different Y-intercept we can see the y intercept are different, but what about the slopes? are they the same?

Answer 2

Oh My God... My head almost exploded and everything just went blank in my mind. I have two equations. Is the first step supposed to be to determine what the X and Y

Answer 3

wait, no need to panic... the fist step is to determine the slope ...rise over run.. right

Answer 4

no, just put both equations in slope intercept form

Answer 5

what does that mean again

Answer 6

Y= 3x-6/3

Answer 7

Y = mx + b

Answer 8

3x + 4y = 6 subtract 3x from each side
4y = -3x + 6 then divide each side by 4 then it is in slope intercept form :]

Answer 9

I got: Y= -3/4 + 1 1/2

Answer 10

y = -3/4x + 6/4
6/4 simplified would be 3/2

Answer 11

what i did is to plot them using transformation of equation: for the first one i plotted x and y = (6-3x)/4 and for the second one i plotted x and y = (3x+7)/4....they are neither parallel or perpendicular...they looked like a cross or multiplication symbol on the chart like this : "x"

Answer 12

and Y = -3x/4 + 7/4

Answer 13

Therefore, the lines neither cross nor run parallel

Answer 14

they do cross...they become like this : "X"

Answer 15

y = 3/4x + 7/4
the slope is positive that's why we get the X due to the slopes being different :]

Answer 16

they would be perpendicular if they cross at 90 deg but they do not!

Answer 17

so the first one (3x + 4y=6) is a negative slope

Answer 18

@ChristaB yes because we're subtracting 3x from each side that's why it becomes negative

Answer 19

@vick2075 it would be if they had the same y-intercept as well, i made an error, and saying they cross at 90deg makes no sense, do you mean form right angles? o.o

Answer 20

yeah form right angles.....90 deg on both sides of the line with respect to the other line

Answer 21

@vick2075 no...

Answer 22

no...what?! anyway how do you put "@vick2075" at the front?

Answer 23

@vick2075 hit the @ symbol then type some letter and hit the name you want

Answer 24

@gaara438125 ....right! thx!

Answer 25

@ChristaB have you got the chart?

Answer 26

This has been working out amazing! Thank you guys SOOOo much. I'm ready for the next problem. So, I will close this one out and write out the next one. If you are up for it, I ask you to hang with me cause you are truly my hero's right now

Answer 27

which chart

Answer 28

@ChristaB the one i attached to one of my replies!

Answer 29

hmm.. no. I didnt see a chart. how would I find that? Im new to this sight and Thank God I found it!!!!)

Answer 30

@ChristaB it's on my second reply above

Answer 31

Ok, that is a totally cool thing... (the attachment thing)

Answer 32

It would not let me open the doc... but the fact that you can send an attachment is pretty nifty