Mathematics
18 Online
OpenStudy (anonymous):
Determine algebraically whether the function is even, odd, or neither even nor odd.
f(x) = -3x4 - 2x - 5
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OpenStudy (lgbasallote):
there's a shortcut to knowing...just look at the exponents of *every* x. What are the exponents of every x in this case?
OpenStudy (anonymous):
4 & 1.
would i add them? and its odd?
OpenStudy (lgbasallote):
nope. remember: any constant is rewritten as cx^0 for example, 1 can be rewritten as 1x^0
2 can be rewritten as 2x^0
so 5 is 5x^0
OpenStudy (lgbasallote):
so the exponents of x are actually 4, 1 and 0
got it?
OpenStudy (anonymous):
alright
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OpenStudy (anonymous):
yeah i get it. so its even?
OpenStudy (lgbasallote):
now, look at 4, 1, 0 <--are these numbers even, odd or neither?
OpenStudy (anonymous):
neither. because 4 even 1s odd
OpenStudy (lgbasallote):
right,
OpenStudy (lgbasallote):
so this polynomial is neither
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OpenStudy (anonymous):
great!
OpenStudy (anonymous):
thanks, can you help me with a few more?
OpenStudy (lgbasallote):
sure
OpenStudy (anonymous):
before that, can you give me an example of an odd function?
would that be like f(x) = -5x^6 - 4x^4 - 7x^2 ?
OpenStudy (lgbasallote):
the exponents in this case are 6, 4 and 2..are those numbers odd?
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OpenStudy (anonymous):
true i meant even lol
so that an even function
OpenStudy (lgbasallote):
yes
OpenStudy (anonymous):
f(x) = -5x^5 - 4x^3 - 7
woul that be odd?
OpenStudy (anonymous):
it would be except for the 7, which ruins it
the degree of a constant is 0, and 0 is an even number
OpenStudy (lgbasallote):
remember, i said constants have x^0 so 7 is actually 7x^0
0 is not odd
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OpenStudy (anonymous):
so f(x) = -5x^5 - 4x^3 - 7x ?
OpenStudy (anonymous):
or f(x) = -5x^7 - 4x^5 - 7x^3
OpenStudy (lgbasallote):
both
OpenStudy (anonymous):
both are odd?
OpenStudy (lgbasallote):
yes
one has exponents 7, 5, 3 <--all are odd
the other is 5,3 ,1 <--all are odd
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OpenStudy (anonymous):
okay. so the next question.
Use the graph of f to estimate the local maximum and local minimum
OpenStudy (anonymous):
OpenStudy (lgbasallote):
don't you just look at the "turning points" of that graph?
OpenStudy (anonymous):
i thought so, but last tiem i got it wrong so i want to double check.
OpenStudy (anonymous):
Local maximum: approx. (-1,1.17); local minimum: approx. (2,-3.33) ?
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OpenStudy (lgbasallote):
hmm...i'm not a master of graphs so i'm afraid i'll have to ask help from @helder_edwin
OpenStudy (anonymous):
alright. theres one more. its graphs too tough. but i have choices, maybe that will help?
OpenStudy (lgbasallote):
i think answers from @helder_edwin will be more precise
OpenStudy (anonymous):
alright
OpenStudy (anonymous):
@helder_edwin ?
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OpenStudy (helder_edwin):
u r right. u got a local maximum at x=-1 and a local minimun at x=2.
OpenStudy (anonymous):
alright. i have one more. can you let me know if im correct?
OpenStudy (helder_edwin):
fire away.
OpenStudy (anonymous):
Determine the intervals on which the function is increasing, decreasing, and constant
OpenStudy (anonymous):
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OpenStudy (anonymous):
i got Increasing x > 0; Decreasing x < 0
OpenStudy (helder_edwin):
no. it is increasing over the entire real line
OpenStudy (helder_edwin):
always read a graph from left to right.
OpenStudy (anonymous):
Increasing on all real numbers?
OpenStudy (helder_edwin):
yes.
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OpenStudy (anonymous):
thank you!
OpenStudy (helder_edwin):
u r welcome
OpenStudy (helder_edwin):
@lgbasallote thanks for the referral.