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Mathematics 18 Online
OpenStudy (anonymous):

Determine algebraically whether the function is even, odd, or neither even nor odd. f(x) = -3x4 - 2x - 5

OpenStudy (lgbasallote):

there's a shortcut to knowing...just look at the exponents of *every* x. What are the exponents of every x in this case?

OpenStudy (anonymous):

4 & 1. would i add them? and its odd?

OpenStudy (lgbasallote):

nope. remember: any constant is rewritten as cx^0 for example, 1 can be rewritten as 1x^0 2 can be rewritten as 2x^0 so 5 is 5x^0

OpenStudy (lgbasallote):

so the exponents of x are actually 4, 1 and 0 got it?

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

yeah i get it. so its even?

OpenStudy (lgbasallote):

now, look at 4, 1, 0 <--are these numbers even, odd or neither?

OpenStudy (anonymous):

neither. because 4 even 1s odd

OpenStudy (lgbasallote):

right,

OpenStudy (lgbasallote):

so this polynomial is neither

OpenStudy (anonymous):

great!

OpenStudy (anonymous):

thanks, can you help me with a few more?

OpenStudy (lgbasallote):

sure

OpenStudy (anonymous):

before that, can you give me an example of an odd function? would that be like f(x) = -5x^6 - 4x^4 - 7x^2 ?

OpenStudy (lgbasallote):

the exponents in this case are 6, 4 and 2..are those numbers odd?

OpenStudy (anonymous):

true i meant even lol so that an even function

OpenStudy (lgbasallote):

yes

OpenStudy (anonymous):

f(x) = -5x^5 - 4x^3 - 7 woul that be odd?

OpenStudy (anonymous):

it would be except for the 7, which ruins it the degree of a constant is 0, and 0 is an even number

OpenStudy (lgbasallote):

remember, i said constants have x^0 so 7 is actually 7x^0 0 is not odd

OpenStudy (anonymous):

so f(x) = -5x^5 - 4x^3 - 7x ?

OpenStudy (anonymous):

or f(x) = -5x^7 - 4x^5 - 7x^3

OpenStudy (lgbasallote):

both

OpenStudy (anonymous):

both are odd?

OpenStudy (lgbasallote):

yes one has exponents 7, 5, 3 <--all are odd the other is 5,3 ,1 <--all are odd

OpenStudy (anonymous):

okay. so the next question. Use the graph of f to estimate the local maximum and local minimum

OpenStudy (anonymous):

OpenStudy (lgbasallote):

don't you just look at the "turning points" of that graph?

OpenStudy (anonymous):

i thought so, but last tiem i got it wrong so i want to double check.

OpenStudy (anonymous):

Local maximum: approx. (-1,1.17); local minimum: approx. (2,-3.33) ?

OpenStudy (lgbasallote):

hmm...i'm not a master of graphs so i'm afraid i'll have to ask help from @helder_edwin

OpenStudy (anonymous):

alright. theres one more. its graphs too tough. but i have choices, maybe that will help?

OpenStudy (lgbasallote):

i think answers from @helder_edwin will be more precise

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

@helder_edwin ?

OpenStudy (helder_edwin):

u r right. u got a local maximum at x=-1 and a local minimun at x=2.

OpenStudy (anonymous):

alright. i have one more. can you let me know if im correct?

OpenStudy (helder_edwin):

fire away.

OpenStudy (anonymous):

Determine the intervals on which the function is increasing, decreasing, and constant

OpenStudy (anonymous):

OpenStudy (anonymous):

i got Increasing x > 0; Decreasing x < 0

OpenStudy (helder_edwin):

no. it is increasing over the entire real line

OpenStudy (helder_edwin):

always read a graph from left to right.

OpenStudy (anonymous):

Increasing on all real numbers?

OpenStudy (helder_edwin):

yes.

OpenStudy (anonymous):

thank you!

OpenStudy (helder_edwin):

u r welcome

OpenStudy (helder_edwin):

@lgbasallote thanks for the referral.

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