Question

1 mole of HCl (g) + 0.5Mole O2(g) are mixed and allowed to attain equillibrium :

4HCl(g) + O2(g) <-----> 2Cl2(g) + 2H2O(g) at 400C Equillibrium pressure =1atm 0.39mole of Cl2 is formed calculate Kp?

Answer 1

@Yahoo! have u got the last question?????????

Answer 2

Yup..

Answer 3

then y u didn't gave me the medal:(.......lol
and let solve it together:)
r u??????

Answer 4

oh..i really forgot abt that..) i will give u then..) wait

Answer 5

yup:)
now first write Kp for it

Answer 6

but first of all i did nt understand wat it really meant by ::: 1 mole of HCl (g) + 0.5Mole O2(g) are mixed and allowed to attain equillibrium :

4HCl(g) + O2(g) <-----> 2Cl2(g) + 2H2O(g)

Answer 7

4HCl(g) + O2(g) <-----> 2Cl2(g) + 2H2O(g)
this is given the standard equation of reaction which tell that 4 moles of HCl react with 1 mole but you have 1mole of HCl and 0.5 mole of O2 that is one is in excess present or we can say the other one is in limiting:)

Answer 8

but it says we have 0.39 moles of Cl2

Answer 9

go with step by step that cl2 help in calculating dissociation so first tell me which one is limiting and which one is in excess????

Answer 10

O2 is excess

Answer 11

4 HCl react with 1 O2

So 0.5 O2 react with 4/1 * 0.5 = 2 Moles of Hcl but we have only 1 mole

Answer 12

right so we always solve whole equation taking the limiting reagent:)
now write how many moles are of CL2 are formed?????

Answer 13

4 Hcl --- > 2 Cl2

i Hcl ----> 2/4 * 1 = 0.5 Mole Cl2

Answer 14

but how many moles are formed???????

Answer 15

0.39

Answer 16

so write the no. of moles of each one at the initial of reaction and at the equillibrium taking dissociation constant a:)

Answer 17

Did nt get u..)

Answer 18

1 mole HCl react with 0.25 Mole of O2to give 0.5Mole of Cl2

Answer 19

But we have 0.5 Moles of O2 means 0.25Mole remian unreacted

Answer 20

in last question i wrote at t=0 and t=equlibrium i want u to wrote this:)

Answer 21

Intial 1 0.5 0.39

Answer 22

nope

Answer 23

1 0.5 (0.39 why)

Answer 24

@Yahoo! 0.39 is after the dissociation at initial no reaction takes place so 1 0.5 nothing more:)

Answer 25

1 0.5 0

Answer 26

@Aperogalics

Answer 27

ya now it is correct now write its equilibrium one:)

Answer 28

1-a 0.5 -a 2a

Answer 29

nope
you are not taking moles in consideration
1-a 0.25+1/4(0.25-a) 1/2(a)

Answer 30

Hm..hm...yes... is 1/2 (a) = 0.39 ??

Answer 31

yup get a=?

Answer 32

@Yahoo!

Answer 33

\[\frac{ 1a }{ 2 } = 0.39\]
\[a = 0.78\]

Answer 34

now write Kp

Answer 35

thxxx.)

Answer 36

it means now you can do it...........:)