Question

What is a correct construction of a line parallel to given line l and passing through given point Q? (1 point)

Answer 1

Do you have to only use a compass and ruler?

Answer 2

Yes

Answer 3

Put your compass on Q first and draw an arc so that it hits the line in two places

Answer 4

At each of those intersecting points draw an arc through point q and make it large enough where the arcs also intersect on the other side

Answer 5

connect the points where the arcs intersect, one of the points is Q. You have now created a perpendicular line

Answer 6

now start on Q again. Draw an arc to that i intersects the new perpendicular line at 2 points.

Answer 7

at each of these intersecting points draw a circle of the same size. Connect the points where these circles intersect

Answer 8

You have now created another perpendicular line to the new line consequestly a parallel line to the original

Answer 9

I did it exactly how you said and I got it right thanks! Can you help me with another one?

Answer 10

sure

Answer 11

Write an equation in point-slope form of the line through point J(4, 1) with slope –4. (1 point)

Answer 12

Point slope form: y – y1 = m(x – x1)

where m is the slope an (x1, y1)

Answer 13

you tell me the answer

Answer 14

y-1 = -4(x-4)??

Answer 15

yup

Answer 16

ok heres another one
Write the equation for the horizontal line that contains point G(–8, 8).

Answer 17

Horizontal line: y=c
Vertical line: x=c

where c is the constant coordinate

Answer 18

y=8 and x=-8

Answer 19

y=8 would be the horizontal

Answer 20

so the final equation would just be y=8

Answer 21

@ChmE