Question

I really don't understand. Any inputs?


Simplify. Express the product as a radical expression.

11√x^5 times √x

Answer 1

We have
\[11 \sqrt {x^5} \times \sqrt x\]
We know that
\[\sqrt A \times \sqrt B=\sqrt{AB}\]
Can you use this here?

Answer 2

My answer:

Answer 3

First step multiply these
\[\sqrt{x^5}\times \sqrt x=???\]

Answer 4

you're doing it a different way

Answer 5

How did you approach the problem?
@InsanelyChaotic

Answer 6

Am I wrong? @mark_o.

Answer 7

\[11\left( x ^{5} \right)^{\frac{ 1 }{ 2 }}\left( x \right)^{\frac{ 1 }{ 2 }}\]
\[=11\left( x \right)^{\frac{ 5 }{ 2 }}\left( x \right)^{\frac{ 1 }{ 2 }}\]
add the power of x, then

Answer 8

I'm sorry, I don't understand

Answer 9

\[=11\left( x \right)^{\frac{ 6 }{ 2 }}\]
divide the power to get
\[=11\left( x \right)^{3}\] ................did you follow this?

Answer 10

= 1

Answer 11

radical expressions can also be written as using the power function
so that you can easilyadd or subtract powers
\[11\sqrt{x ^{5}}*\sqrt{x}\]
\[=11\left( x ^{5} \right)^{\frac{ 1 }{ 2 }}*\left( x \right)^{\frac{ 1 }{ 2 }}\]

Answer 12

Do I add both halfs?

Answer 13

halves*

Answer 14

yes you can

Answer 15

1/2 + 1/2 = 1 whole

Answer 16

its the power of
\[\frac{ 5 }{ 2 }+\frac{ 1 }{ 2 }=\frac{ 6 }{ 2 }=3\]

Answer 17

\[=11\left( x ^{5} \right)^{\frac{ 1 }{ 2 }}*\left( x \right)^{\frac{ 1 }{ 2 }}\]
multiply first the power of 5 and 1/2, to get
\[=11\left( x \right)^{\frac{ 5 }{ 2 }}*\left( x \right)^{\frac{ 1 }{ 2 }}\]
now add the powers of both x
\[=11\left( x \right)^{\frac{ 6 }{ 2 }}\]
dividing the power
\[=11\left( x \right)^3\]
\[=11x ^{3}\]

Answer 18

the rule on powers is to multiply first then add right?