What is the solution to the equation 4^(2x) ≈ 3 ?

x = –0.631

x = –0.396

x = 0.396

x = 0.631

Question

What is the solution to the equation 4^(2x) ≈ 3 ?

 x = –0.631

 x = –0.396

 x = 0.396

 x = 0.631

anonymous · Answer

take logs of both sides.

anonymous · Answer

Also, use the relationship:$$\ln a ^{b} = b \times \ln a$$

anonymous · Answer

no need of logs just replace x with the value given and solve

anonymous · Answer

@Sufiyancs , that's no way to get an answer!  What if you were not given any choices!  The goal here is not to get the answer, it's to learn how to solve problems!

anonymous · Answer

fine u continue man.. i'm out

anonymous · Answer

what?

anonymous · Answer

$$4^{2x} = 3$$can be solved by$$\ln 4^{2x} = \ln 3$$which equals$$2x \times \ln 4 = \ln 3$$

anonymous · Answer

Divide each side by 2(ln 4) and you get your value for "x"

anonymous · Answer

Is it B?

anonymous · Answer

Can you get the value for ln 3  ?

anonymous · Answer

what do you mean by ln 3?

anonymous · Answer

Just what everyone in the world of math means by it.  ln 3 is simply ln 3, the natural logarithm of 3.  The exponent you put on "e" to get 3.  Logs are exponents.

anonymous · Answer

Do you have any familiarity with logarithms?