what is the area of the circle that has the equation below:
x^2+y^2+2x-12y+12=0

5pi
12pi
25pi
144pi

Question

what is the area of the circle that has the equation below: 
x^2+y^2+2x-12y+12=0

5pi
12pi
25pi
144pi

anonymous · Answer

you'll need to put this general equation of a circle in center-radius form by completing the square...
then you'll have the radius in which case you can calculate the area

anonymous · Answer

group the expressions with x and the expressions with y together....

anonymous · Answer

x2+2x+y2-12y=-12
x^2+2x+1-1+y2-12y+36-36=-12
(x+1)^2+(y-6)^2=-12+36+1
                                =25
                                    5^2
radius =5
area =2pie 5

anonymous · Answer

area =pie 25
make correction