the surface area of a cylinder is increasing by 2 pi square inches per hour and the height is decreasing by 0.1 inches per hour when the radius is 16 inches and the height is 7 inches. how fast is the radius of the cylinder changing?

Question

anonymous · Answer

Related Rates:

dSA
-- = 2pi
dt

dh
-- = -.1
dt

r = 16, h=7

Find: dr/dt

Knowing that SA = 2(pi r^2)+2pi rh

anonymous · Answer

do i find the derivative of the SA before plunging the values?

anonymous · Answer

how to find h with respect to r?

anonymous · Answer

you don't... differentiate with respect to time....

anonymous · Answer

how?