the surface area of a cylinder is increasing by 2 pi square inches per hour and the height is decreasing by 0.1 inches per hour when the radius is 16 inches and the height is 7 inches. how fast is the radius of the cylinder changing?

Question

anonymous · Answer

Just try using the chain rule, keeping in mind that Area = f(Height, Radius). 
In this case you know dA/dt and dH/dt at some particular moment. So, express dR/dt in terms of the stuff you know. The key word is - chain rule for partial derivatives.

anonymous · Answer

If you'll have problems with that I can try to solve it for you, but I'll do it only after you demonstrate that you tried it on your own.

anonymous · Answer

If I got everything right, the answer should be approximately 0.046 inches/hour.

stacey · Answer

Write the equation/formula for the surface area. Take the derivative with respect to time, and do the substitutions so that you can solve for dr/dt.

anonymous · Answer

I got .07"/hr.  Is the cylinder a solid?