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Mathematics 20 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Are you familiar with Pascal's Triangle and the Binomial Theorem? What about the combinations formula?

OpenStudy (anonymous):

I know about Pascal's Triangle

OpenStudy (anonymous):

That's a good start. It'll give you the binomial coefficients. The binomial (5v+s) to the 5th power will be a 6 term polynomial. From the 5th row of Pascal's Triangle, you see the binomial coefficients: 1 5 10 10 5 1.

OpenStudy (anonymous):

The exponents on (5v) start at 5 and go down to 0. The exponents on (s) start at 0 and go up to 5, as the terms progress. So the first term will be \((1)(5v)^5(s)^0\) And the second term will be \((5)(5v)^4(s)^1\) Understand how I got those?

OpenStudy (anonymous):

Was it by the Binomial Theorem? I learned a little about it yesterday, but I don't remember all of it.

OpenStudy (anonymous):

Yes, binomial theorem.

OpenStudy (anonymous):

Looking at those answer choices.. are you sure it's not actually looking for the second-to-the-last term?

OpenStudy (anonymous):

It didn't specify, but I think it could be. Is it only one of the answers if you look at the second-to last term?

OpenStudy (anonymous):

Yes, I see the 2nd-to-last term in that list.

OpenStudy (anonymous):

Is it 24s^4v?

OpenStudy (anonymous):

That is very close.

OpenStudy (anonymous):

Is it just 25s^4?

OpenStudy (anonymous):

\(25s^4v\)

OpenStudy (anonymous):

(you said 24 . . .)

OpenStudy (anonymous):

Oops XD Thank you for helping me

OpenStudy (anonymous):

Binomial theorem is really easy once you get the pattern.

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