lock m1 of mass 2m and velocity v0 is trav- eling to the right (+x) and makes an elastic head-on collision with block m2 of mass m and velocity −2 v0 (i.e., traveling to the left). What is the velocity v1 0 of block m1 after the collision?

1. v10 = −3/2v0 2. v10 = −v0 3. v10 =3/2vo 4. v10 = 3 v0 5. v10 = 2 v0 6. v10 = v0 7. v10 = −3 v0 8. v10 = −2 v0

Question

lock m1 of mass 2m and velocity v0 is trav- eling to the right (+x) and makes an elastic head-on collision with block m2 of mass m and velocity −2 v0 (i.e., traveling to the left). What is the velocity v1 0 of block m1 after the collision?

1. v10 = −3/2v0 2. v10 = −v0 3. v10 =3/2vo 4. v10 = 3 v0 5. v10 = 2 v0 6. v10 = v0 7. v10 = −3 v0 8. v10 = −2 v0

anonymous · Answer

v1i-v2i=v2f-v1f (conservation of velocity for elastic collision)

anonymous · Answer

would you use the conseration of momentum to solve for one of the final velocitys then plug it back into the conservation of velocity equation?