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Mathematics 9 Online
OpenStudy (appleduardo):

how can i derivate the next function?

OpenStudy (appleduardo):

\[\frac{ 2x+4 }{ \sqrt{2x+4} }\]

OpenStudy (anonymous):

do you know the quotient rule?

OpenStudy (appleduardo):

not at all :/

OpenStudy (anonymous):

take a look at this: http://en.wikipedia.org/wiki/Quotient_rule theres a simple formula for it do you know the chain rule?

OpenStudy (anonymous):

Hint: \[ \sqrt{2x+4} \cdot \sqrt{2x+4} = 2x+4\]So\[ \frac{ 2x+4 }{ \sqrt{2x+4} } = \sqrt{2x+4} \]

OpenStudy (appleduardo):

mm i did the process step by step,, then i got = \[\frac{ 1 }{ \sqrt{2x+4} }\]

OpenStudy (anonymous):

@wio, that was creative, i never would have thought to simplify like that

OpenStudy (anonymous):

im fairly sure thats right @appleduardo

OpenStudy (appleduardo):

so am i wrong? mm

OpenStudy (anonymous):

no

OpenStudy (appleduardo):

ooh right! i understood! :D then if derivate what wio typed, ill get the same result i got! right?

OpenStudy (anonymous):

yes

OpenStudy (appleduardo):

thank you so much! :D you guys helped me a lot! :D thanks again

OpenStudy (anonymous):

welcome :)

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