Question

What is the radius of the circle whose equation is x^2 + y^2 = 8?

Answer 1

Standard equation of a circle with center at origin and radius r
\[x^2+y^2=r^2\]
here we have the equation as
\[x^2+y^2=8\]
Compare the two equation and find the radius. Can you do that? @Cherishyou

Answer 2

64

Answer 3

Look carefully r^2=8, find r from that :)

Answer 4

dont you sqaure the 8 ?

Answer 5

We have the equation as
\[x^2+y^2=8\]
Standard equation with radius r
\[x^2+y^2=r^2\]
Compare both so
\[x^2=x^2\]
\[y^2=y^2\]
\[r^2=8\]

Answer 6

2 square root of 2

Answer 7

yes:D

Answer 8

Thank Youuu . I Was Confused For A Minute ( : lol

Answer 9

Np:D