Question

If coshx=5/3 and x>0, find the values for sinhx, tanhx and cschx

Answer 1

I know it's hyperbolic, and there are formulas involved. Just not sure how to actually do the problem.

Answer 2

\[\cosh^{2}(x) - \sinh^{2}(x) = 1\] That should do for sinh(x)

Answer 3

first take square
cosh^2x= 25/9
for sinh^2x=1-cosh^2x as sinh^2x+cosh^2x=1
take sqreeroot to get sinhx
now cschx=1/sinhx
tanhx=sinhx/coshx

Answer 4

why would i use that formula?

Answer 5

which one?

Answer 6

for sinhx

Answer 7

so sinhx should = -4/3

Answer 8

4i/3

Answer 9

right,

Answer 10

tan = 4i/5
and csc = 3/4i?