Find the volume using cylindrical coordinates: The solid region bounded below by the surface z=sqrt(r) and above by the plane z=1.

Question

anonymous · Answer

I tried but couldn't determine where the r's would go from and to. The theta is from 0 to 2pi and z is from 1 to radical r.

Now I need help as well.

anonymous · Answer

Lol. I'm mostly hung up on what I'm supposed to do this problem. What am I integrating and  how would I determine the bounds of this problem? Im going ahead in class and doing this section but I might have to call it off until lecture.

zepdrix · Answer

Hmm so it's already given to us in cylindrical coordinates, I'll bet we can figure this out! :D Just a sec.. thinking.

anonymous · Answer

Thanks, take your time.

anonymous · Answer

Oh and to add - the answer is pi/5. Im mostly looking for the steps.

zepdrix · Answer

Oh you have the answer, good that's helpful :)

zepdrix · Answer

ok i got pi/5, lemme see if i can guide you through this.
It's a little difficult to draw if you're not comfortable with cylindrical coordinates.
Maybe we won't worry about that portion of it.

zepdrix · Answer

|dw:1352331768636:dw|
This is the object we end up with.
z=r is the graph of a cone.
So then z=sqrtr is a cone but it's nice n curvy c: