Question

I only need help with #2. The image of the question attached

Answer 1

First you write the balanced eq out. H2SO4+2KOH --> K2So4+2H2O

Moles of H2SO4 = 25 ml/1000 x 0.125 Moles/L
NExt the stoichiometric ratio 1 mole of H2SO4 = 2 Moles of KOH
So moles of KOH = moles of H2SO4 x 2 moles KOH/1 mole H2SO4
Now M of KOH = moles (from the previous step) / (27.07 ml /1000ml)L

Answer 2

Is that how u find teh concentration of it ?

Answer 3

As in does that response give u teh concentration on KOH?

Answer 4

What is M? MOlarity. Or concentration.

Answer 5

Molarity

Answer 6

So M of KOH must mean molarity which is a way to express concentration. Am i understanding it correctly