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Mathematics 20 Online
OpenStudy (anonymous):

Help please?!

OpenStudy (anonymous):

Create your own radical equation. Describe in complete sentences and demonstrate the process in finding its solution(s).

OpenStudy (anonymous):

Consider the equation sqrt(-2x + 3) = x To solve this, first we would square both sides. -2x + 3 = x^2. Getting everything to one side, we are trying to solve x^2 + 2x - 3 = 0. Factoring, we get (x - 1)(x + 3) = 0. Setting each term equal to 0, we see that we get possible solutions x = 1 and x = -3. Finally, we plug back in to the original equation to see if these are true solutions. When x = 1, we get sqrt(-2 + 3) = sqrt(1) = 1, which means 1 is a solution. When x = -3, we get sqrt(-2(-3) + 3) = sqrt(9) = 3, which is NOT -3, so -3 is not a solution. The only solution to this radical equation is x = 1.

OpenStudy (anonymous):

Thank you :D

OpenStudy (anonymous):

;)

OpenStudy (anonymous):

wait, i can't see the picture

OpenStudy (anonymous):

@amber96

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