Question

Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x^2 + y^2 - 10x - 8y + 29 = 0

A. (x - 5)^2 +(y - 4)^2 = 12 (5, 4), r = 12
B. (x - 5)^2 +(y - 4)^2 = 12 (5, 4), r = 2 sq rt 3
C. (x + 5)^2 +(y + 4)^2 = 12 (-5, -4), r = 2 sq rt 3

Answer 1

is this calculis

Answer 2

Yes pre-calc

Answer 3

start with
\[x^2 + y^2 - 10x - 8y + 29 = 0\] then group the terms together as
\[x^2-10x+y^2-8y=-29\] to complete the square, take half the coefficient of the \(x\) and \(y\) term and write
\[(x-5)^2+(y-8)^2=-29+5^2+4^2\] then compute the number on the right

Answer 4

ooh thats y im in geometry srry

Answer 5

you get
\[(x-5)^2+(y-4)^2=12\] so the circle has center at \((5,4)\) and radius \(\sqrt{12}\) or \(2\sqrt{3}\) if you prefer

Answer 6

thank you

Answer 7

yw

Answer 8

see u marrow alyssa :) bye