Question

Factor each Polynomial. Show your work. Solve using
Difference of Squares: A^2 - B^2 = (a -b) (a + b)
Differences of Cubes:
A^3 - B^3 = (A - b) (a^2 + ab + b^2)
Sum of Cubes:
A^3+ B^3 = (a + b) (a^2 - ab + b^2)

12. 5x^3 - y^3

Answer 1

I mean I have (5x - y) as a starting point; that's all I have so far

Answer 2

(5x-y)(25x^2+(-5xy)+y^2)

Answer 3

(25x^2+(-5xy)+y^2)

Answer 4

ijust plugh in 5 for my a and -1 for my b

Answer 5

so you got this: (5x -y) (5x^2 + (5xy) + y^2) to get: (25x^2+(-5xy)+y^2) <--- why is it + (-5xy)

Answer 6

sorry the 5x is the a okay the -5xy is cuyz yu havwe -1 x 5 so you get -5and the variables.

Answer 7

oh okay gotcha totally understand: How would (25x^2+(-5xy)+y^2) = 5x^3 - y^3

Answer 8

no the thing i sent yu first was the whole answer.

Answer 9

I know my bad how does this: (5x-y)(25x^2+(-5xy)+y^2) = 5x^3 - y^3

Answer 10

no yu dont need that equals. there is no equal to this problem

Answer 11

I know how does that answer give you 5x^3 - y^3 though

Answer 12

there is no answer
well yu can write it oyut cuz it is the same thing.

Answer 13

why would it not be (5x -y) (x^2 +(-5xy) + y^2

Answer 14

becauise yu need the five.on the x^2 because yur A is 5x

Answer 15

okay

Answer 16

got it?

Answer 17

cause it doesn't look like it's right though

Answer 18

Is he right or wrong would you say???

Answer 19

I can't figure it out

(5x-y)(25x^2+(-5xy)+y^2)
125x^3 - 25x^2y + 5xy^2 - 25x^2y + 5xy^2 - y^3

His answer is wrong.

I can't fix it

Answer 20

do you know what it's suppose to be

Answer 21

I said it was (5x - y) (x^2 + (-5xy) + y^2)

Answer 22

I think I got it hold on

Answer 23

cause I think mine was correct, but was for sure

Answer 24

wasn't for sure

Answer 25

nvm. I don't think it can be factored.

http://www.solvemymath.com/online_math_calculator/general_math/factoring_calculator/factoring.php

This site couldn't factor it either

Answer 26

what would you think it would be???

Answer 27

I will ask somebody else alright

Answer 28

Call in @Hero

Answer 29

I have another problem that's confusing too

Answer 30

Double check and make sure you posted the problem correctly.

Answer 31

so how would you factor it? @Hero

Answer 32

You can only factor it if it is a difference of cubes. What you posted does not satisfy the requirements for the definition of difference of cubes.

Answer 33

so is there no answer

Answer 34

The correct answer is: Prime, Not factorable

Answer 35

okay thank you Hero. I have another problem that I don't get