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Chemistry 69 Online
OpenStudy (anonymous):

An apprentice jewler determines the density of a sample of pure gold to be 20.3 g/cm. The accepted value is 19.3 g/cm. What is the percent error?

OpenStudy (jfraser):

Percent error (%Err) is:\[\%Err = |\frac{actual - experiment}{actual}| * 100\%\] plug and solve

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