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OpenStudy (anonymous):

I'm confused on a Laplace Transform problem we did in class. I will post the problem and all the work. I'm looking for an explanation

OpenStudy (anonymous):

OpenStudy (anonymous):

In the picture I wrote my questions

hartnn (hartnn):

those are standard formulas, u didn't get them ? see the table of laplace inverse....

OpenStudy (anonymous):

And the answer to that will cost you $45/hour lol

hartnn (hartnn):

and don't worry, u need not pay here anything....

hartnn (hartnn):

L(e^{at})=1/(s-a) so L^{-1} of {1/(s-a)} = e^{at}

hartnn (hartnn):

oh, u mean to ask, why s is taken -1 ? or -2 ?

OpenStudy (anonymous):

I have the table. I guess I am not seeing how to apply them. And @hartnn . Yes why isn't -2, -1 plugged into the left side and set equal. Why is it -2 = and -1 =

hartnn (hartnn):

yup. it must be 22=-8B

OpenStudy (anonymous):

Maybe I misunderstood what he was saying, but I copied the board exactly. I'll have to ask. That makes sense to me Hartnn

OpenStudy (anonymous):

Ok fine! You see where you wrote your partial fractions? Those have to be matched up with the equations you're questioning. I probably have this exact problem worked out in my office. I'll go look

OpenStudy (anonymous):

You're too kind @aerokat25

hartnn (hartnn):

yeah, u put value of s on both sides...

OpenStudy (anonymous):

So i look at my partial fractions and decide what laplace transforms to use? I see that

hartnn (hartnn):

not exactly....partial fraction not dependent on transform...u use partial fraction and look for appropriate formula of inverse transform

OpenStudy (anonymous):

Thanks for the clarification

OpenStudy (anonymous):

I'm going to work out the problem with 22 and 19 and use the solution at the bottom of the page. I will post my answer when I finish

hartnn (hartnn):

ok.

OpenStudy (anonymous):

Yes what hart said....but I know u know that based on your work.

OpenStudy (anonymous):

\[\frac{ 19 }{ 5 }e^{-t}-\frac{ 11 }{ 4 }e^{-2t}-\frac{ 1 }{ 20 }\cos 2t+\frac{ 3 }{ 20 }\sin 2t\]What is it equal to?

OpenStudy (anonymous):

Hang on I found a question just like yours except its not solved with Laplace. Hang

OpenStudy (anonymous):

Probably solved with undetermined coefficients. Thanks for your help

OpenStudy (anonymous):

I have one very similar but I can't find it damn it. I have all my comps stuff out right now. I'm still looking.

OpenStudy (anonymous):

Ok found something. How do I upload a pic onto this?

OpenStudy (anonymous):

attach file button

hartnn (hartnn):

that is equal to y

OpenStudy (anonymous):

I should have known that. thx

hartnn (hartnn):

welcomes ^_^

OpenStudy (anonymous):

Did you figure it out @aerokat25

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