I'm confused on a Laplace Transform problem we did in class. I will post the problem and all the work. I'm looking for an explanation
In the picture I wrote my questions
those are standard formulas, u didn't get them ? see the table of laplace inverse....
And the answer to that will cost you $45/hour lol
and don't worry, u need not pay here anything....
L(e^{at})=1/(s-a) so L^{-1} of {1/(s-a)} = e^{at}
oh, u mean to ask, why s is taken -1 ? or -2 ?
I have the table. I guess I am not seeing how to apply them. And @hartnn . Yes why isn't -2, -1 plugged into the left side and set equal. Why is it -2 = and -1 =
yup. it must be 22=-8B
Maybe I misunderstood what he was saying, but I copied the board exactly. I'll have to ask. That makes sense to me Hartnn
Ok fine! You see where you wrote your partial fractions? Those have to be matched up with the equations you're questioning. I probably have this exact problem worked out in my office. I'll go look
You're too kind @aerokat25
yeah, u put value of s on both sides...
So i look at my partial fractions and decide what laplace transforms to use? I see that
not exactly....partial fraction not dependent on transform...u use partial fraction and look for appropriate formula of inverse transform
Thanks for the clarification
I'm going to work out the problem with 22 and 19 and use the solution at the bottom of the page. I will post my answer when I finish
ok.
Yes what hart said....but I know u know that based on your work.
\[\frac{ 19 }{ 5 }e^{-t}-\frac{ 11 }{ 4 }e^{-2t}-\frac{ 1 }{ 20 }\cos 2t+\frac{ 3 }{ 20 }\sin 2t\]What is it equal to?
Hang on I found a question just like yours except its not solved with Laplace. Hang
Probably solved with undetermined coefficients. Thanks for your help
I have one very similar but I can't find it damn it. I have all my comps stuff out right now. I'm still looking.
Ok found something. How do I upload a pic onto this?
attach file button
that is equal to y
I should have known that. thx
welcomes ^_^
Did you figure it out @aerokat25
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