Question

Jim

Answer 1

\[V_{avg}=\frac{\Delta x}{\Delta t}\]

Answer 2

right?

Answer 3

Yes.

Answer 4

so i'm doing an experiment where it'd save a lot of time by meaning the values

Answer 5

averaging the times and what not

Answer 6

would that be

\[V_{avg}\] mean

Answer 7

Like v(mean)? It should be because mean means average.

Answer 8

well what i'm saying is means are where you add all values and divide by n

Answer 9

Yep.

Answer 10

but that isn't what average velocity is it not? because avg velocity is just the change in distancee

Answer 11

Yeah mean also means average. It's the same thing I would presume.

Answer 12

in other words what would this be

\[\frac{ \frac{\sum x_i}{n}}{\frac{\sum t_i}{n}}\]

Answer 13

Yeah. It should be.

Answer 14

they're equal to each other but i'm just wondering how to derive to this conclusion

Answer 15

Well couldn't you just say mean IS average so V(ave) is = V(mean) .

Answer 16

ahh yes so start from v mean

Answer 17

\[\frac {\sum v_i}{n}=\frac{\sum \frac{d_1}{t1}.......}{n}\]

Answer 18

how would i split this up though?

Answer 19

You lost me :( .

Answer 20

can you do something like this

\[\sum d_1t^{-1}=\sum d_1 *\sum t_i^{-1}=\frac{\sum d_i}{\sum t_i}\]

Answer 21

or is this algebraically incorrect?

Answer 22

I don't think you can do that....