How would u get rid of the pi in this equation: 25pi(r)(r+2pi(r)^2
it should be equal to something ?
all this equals the surface area of a given cylinder
can u type r without brackets and only use where neceessary
okay, the original was . S=2pir(r+25/pir^2)
pi is getting cancells directly as one pi is in Numerator and other is in denominator!!
ooo k. i see that. but for the answer they have 2pir^2+50r^-1. they brought up the pir^2 from the denominator to make 2pir(r+25pir^-2)
u need to type the question correctly earlier u typed it differently please upload the questionor attach file
Originially It yped it this way, i see now that as a typo I wrote 2pir^-2 instead of 25. The Original : S= 2pir(r+25/pir^2) They simplified it so that now it's S= 2pir^2+50r^-1 I understand the 2pir was distributed nto in the parenthesis, but I do not understand why the pi was cancelled in the simplified version.
\[ S= 2r \pi(r+ \frac{ 25 }{ \pi^2 })\] Is this the correct version? If so, then \[ S= (2r \pi)r + (2r \pi)(\frac{ 25 }{ \pi^2 })\] notice that the pi will cancel at the back, leaving, \[S=2\pi r ^2 + \frac{ 50r }{ \pi}\]
its just simple multiplication results in cancellation of pi!!
ok, thank you
You're welcome!
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