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OpenStudy (anonymous):
The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the molecular formula of the compound, showing your work.
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OpenStudy (anonymous):
lets make it simple, first calculate "molar mass" of empirical unit: 12+2*1+16 = 30 so 90/30 = 3 so you have 3*(CH2O) --> C3H6O3
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