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Mathematics
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OpenStudy (anonymous):
I'm having trouble understanding step/equation 8
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hartnn (hartnn):
it follows from step/equation 7.
OpenStudy (anonymous):
hartnn (hartnn):
since they are solutions, they must = 0
OpenStudy (anonymous):
It's the explanation/ derivation of the method of Variation of Parameters. How are y_1 and y_2 solutions of the complimentary equation
OpenStudy (anonymous):
I believe that y_1 is, but why y_2?
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hartnn (hartnn):
why not ?
hartnn (hartnn):
aren't they BOTH assumed/derived to be solution for CE ?
OpenStudy (anonymous):
sorry my internet is soo slow, or it could be the website....anyhow I'm back. Let's see....
OpenStudy (anonymous):
oh I thought that \[y(x)=c_1y_1(x)+c_2+y_2(x)\]
meant:
y(x)= complimentary equation + particular solution
OpenStudy (anonymous):
sorry typo
y(x)=c_1y_1(x)+c_2y_2(x)
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OpenStudy (anonymous):
\[y(x)=c_1y_1(x)+c_2y_2(x)\]
OpenStudy (turingtest):
that is just the complimentary soln.
OpenStudy (anonymous):
do you want me to attach the whole page?
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
I guess the fact that they wrote it as y(x) (instead of y_c) confused me
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