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Mathematics 9 Online
OpenStudy (anonymous):

I'm having trouble understanding step/equation 8

hartnn (hartnn):

it follows from step/equation 7.

OpenStudy (anonymous):

hartnn (hartnn):

since they are solutions, they must = 0

OpenStudy (anonymous):

It's the explanation/ derivation of the method of Variation of Parameters. How are y_1 and y_2 solutions of the complimentary equation

OpenStudy (anonymous):

I believe that y_1 is, but why y_2?

hartnn (hartnn):

why not ?

hartnn (hartnn):

aren't they BOTH assumed/derived to be solution for CE ?

OpenStudy (anonymous):

sorry my internet is soo slow, or it could be the website....anyhow I'm back. Let's see....

OpenStudy (anonymous):

oh I thought that \[y(x)=c_1y_1(x)+c_2+y_2(x)\] meant: y(x)= complimentary equation + particular solution

OpenStudy (anonymous):

sorry typo y(x)=c_1y_1(x)+c_2y_2(x)

OpenStudy (anonymous):

\[y(x)=c_1y_1(x)+c_2y_2(x)\]

OpenStudy (turingtest):

that is just the complimentary soln.

OpenStudy (anonymous):

do you want me to attach the whole page?

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

I guess the fact that they wrote it as y(x) (instead of y_c) confused me

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