determine wheather each order pair is a soultion for 2y-x=10 (2,-6) and (0,5)
plug in and check (2,-6) 2(-6)-2 = ? (0,5) 2*5 - 0 =?
Yeah and if they both equal 10 then they are solutions, and if either one of them do not then they are not solutions to that equation.
how do yow show work for that qustion
2y-x=10
by plugging in
You just plug in your first order pair to the x and y and do the same for the second order pair. That is showing your work.
(2,-6) 2y -x =10 2(-6)-2 = ? if you get 10, it is a solution if not, its not a solution (0,5) 2y -x =10 2*5 - 0 = ? if you get 10, it is a solution if not, its not a solution
@race_mom_23 did you get it?
so the anwser ar -14 and 10
so which one of these 2 satisfy the equation 2y - x = 10
(0,5)
Yep!
correct
i have some more qustions?
show that the orders pair(0,-3) and (2,1) are solution of the equation 2x-y=3. Then use the graph of equation to determine another solution.
you just do the same thing as before. And then just pick a point that lies on the line for another point.
so i take 3+-3
Well to determine a point you need to solve the equation for y and then graph it and then just pick a point that is on that line.
im still lost sorry
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