Ask your own question, for FREE!
Physics 18 Online
OpenStudy (anonymous):

please show ur Work >>>> Dimension of a pressure ?

OpenStudy (anonymous):

i need to see the steps of solving it plz :)

OpenStudy (ash2326):

Do you know the relation between Pressure and force?

OpenStudy (anonymous):

i know \[p = \frac{ F }{ a }\] So \[= \frac{ m a }{a }\]

OpenStudy (ash2326):

\[P=ma / A\] \[a\ne A\] can you tell me the difference between a and A?

OpenStudy (anonymous):

idk , u tell me :B

OpenStudy (anonymous):

i just wanna know how we got L to the power -1 and T to the power -2

OpenStudy (anonymous):

how we got the negative powers ?

OpenStudy (ash2326):

a= acceleration= distance/ (time )^2= L/T^2=\(LT^{-2}\) A= area= \(L^2\)

OpenStudy (anonymous):

oh yeah

OpenStudy (ash2326):

Can you try now?

OpenStudy (anonymous):

gemme a minute

OpenStudy (ash2326):

sure :)

OpenStudy (anonymous):

= \[\frac{ M L T ^{-2} }{L T ^{-2} }\]

OpenStudy (anonymous):

is that right -0-

OpenStudy (ash2326):

Why you have \(Lt^{-2}\) in the denominator?

OpenStudy (anonymous):

because pressure = \[\frac{ m a }{a }\] and \[a = l T ^{-2}\]

OpenStudy (anonymous):

u just said that >_>

OpenStudy (ash2326):

Read my post again,

OpenStudy (anonymous):

is p pressure Force over area ?

OpenStudy (ash2326):

Yes :)

OpenStudy (anonymous):

i thought its force over acceleration -.-

OpenStudy (anonymous):

okie my bad

OpenStudy (ash2326):

No problem, you got it now?

OpenStudy (anonymous):

yeah -,- thanks again

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!