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Mathematics 17 Online
OpenStudy (anonymous):

Possion Distribution Prove or disprove

OpenStudy (anonymous):

Consider four random variables\[x _{1}, x _{2}, x _{3}, x _{4} \] where \[ X_{1} + X_{2}, X_{3}, X_{4}\] are independent. It holds that\[\sum_{i=1}^{4} X_{i}\] ~Possion (10) and \[X_{3}\] ~Possion (3) and \[X_{4}\] ~Possion (3) Prove or disprove: The distribution of\[X_{1} + X_{2}\] can be detremined

OpenStudy (anonymous):

@mahmit2012 please help

OpenStudy (anonymous):

@Zarkon please help!!!

OpenStudy (zarkon):

I would look at the MGF

OpenStudy (anonymous):

can you show it

OpenStudy (zarkon):

why don't you try first.

OpenStudy (anonymous):

I am actually trying to get help for a friend and I am not too familiar with subject but I can try so I am to get the MGF of what part?

OpenStudy (zarkon):

what is the MGF of \(X_1+X_2+X_3+X_4\) and the MGF of \(X_3+X_4\)

OpenStudy (anonymous):

\[((X2 (-z)+X2-X3 z+X3-X4 z+X4+z)) / ((z-1)^2)\]

OpenStudy (anonymous):

is this the first one?

OpenStudy (zarkon):

??? No

OpenStudy (anonymous):

ok I have no idea can you help

OpenStudy (anonymous):

\[e ^{\lambda e^t -1}\] where t is X1 X2 X3 and X4

OpenStudy (zarkon):

\(\lambda\) should have a specific value..also t is not X1 X2 X3 and X4

OpenStudy (anonymous):

I am really lost with this problem if you could walk the steps out that would be great

OpenStudy (anonymous):

Ok I have been fighting with this problem for and hour... will you please show me how to do it I am trying to learn and am getting no where @Zarkon

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