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Calculating DE on this right triangle?
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ok... this problem uses similar triangles and the common side GE.... so looking at triangles DGE and GFE |dw:1352403630016:dw| looking at the side ratios of triangle I to triangle II you have \[\frac{3}{GE} = \frac{GE}{8}\] so \[EG^2 = 24\] after cross multiplying now use pythagoras's theorem on triangle DGE to find DE \[DE^2 = DG^2 + EG^2\] you already have EG^2 so \[DE^2 = 3^2 + 24\] I'll leave you to finish it.
how about sqrt of 33
15 was for a different question, sorry. I'm still trying to solve this one, almost got it.
And I got 33. So thankyou!
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hope it helps... its a tough question
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