I need help with the follow equation: (Please explain how you got to the answer.)

Question

anonymous · Answer

$$\frac{ 160 x^{2} }{ 20 }\div \frac{ 4 }{ 5y ^{2} }$$

anonymous · Answer

Are you just looking to simplify this? It's not really an equation(no equal sign), so there's nothing to solve for.

To simplify here i would simply combine the two fractions. Dividing a fraction is the same as flipping it over and multiplying so:

$$160x^2/20 \div 4/5y^2 = 160x^2 * 5y^2 / 20 *4$$

160*5 on the top and 80 on the bottom works out to just 10 on the top:

$$10x^2y^2$$

anonymous · Answer

Okay so I just need to flip any fraction like that in which I am dividing to get my answer and then cross multiply?

anonymous · Answer

Yeah, if you're dividing one fraction by another just flip the second one and multiply. 

Cross multiplying usually refers when you've got one fraction equal to another one so if you have $$x/350 = 90/100$$Cross multiplying turns it into:
$$90*350 = 100x$$$$315 = x$$Like if you wanted to find out how many points out of 350 would give you 90%(90/100)

anonymous · Answer

So does cross multiply work for this sort of problem?

anonymous · Answer

Oh and this is a "equals" problem. Forgot to add the sign.

anonymous · Answer

Assuming that's supposed to be an = in the center instead of the division sign, then yeah you would cross multiply here.
It'ld$$ y = \pm \sqrt{1/10x^2}, x = \pm \sqrt{1/10y^2}$$be $$80 = 160*5x^2y^2$$$$ 1 = 10x^2y^2$$Solve for whatever: $$y = \pm \sqrt{1/10x^2}$$ The graph ends up looking like a big diamond.

anonymous · Answer

This is what the problem looks like on MyMathLab. Whatever you did up there seem to be way over my head. I am in College Intermediate Algebra...

anonymous · Answer

Ah, kk, they only wanted you to simplify. The first answer is pretty much what they  were looking for then.

anonymous · Answer

I tried it and that did not work. It is supposed to still be in a fraction form?

anonymous · Answer

The denominator turns into 1 when you simplify so there's no fraction to write. You do have x^2 in your OP and x^3 on the question you just pasted over, but outside of that there's really not much else going on.

anonymous · Answer

Okay so is the x only x and not x^2?

anonymous · Answer

Never mind I got it... I don't know what I was thinking. Thank you for your patients with me and your help!