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Mathematics 15 Online
OpenStudy (faman39):

Two lines are related by the scale 4 centimeters5 decimeters. How many times larger is the larger line? 1.25 12.5 125 1,250

OpenStudy (lukebluefive):

1 decimeter = 10 centimeters So: 5 decimeters = 50 centimeters

OpenStudy (faman39):

So how will i do this?

OpenStudy (lukebluefive):

To find the ratio of how much longer something is than something else, you divide it. For example: \[\frac{100ft}{10ft} = 10\] Which means that something 100 feet long is 10 times longer than something 10 feet long.

OpenStudy (faman39):

Are we have to divide 4/5

OpenStudy (lukebluefive):

Well, you can only divide values with like terms, and centimeters ≠ decimeters. Also, to avoid confusion, put the larger number on top when dividing.

OpenStudy (faman39):

got 1

OpenStudy (lukebluefive):

Your answer was 1?

OpenStudy (faman39):

no you told to divide 5/4

OpenStudy (faman39):

isnt tht u mean ?

OpenStudy (lukebluefive):

Well, if you divide: \[\frac{5 decimeters}{4centimeters}\] You'll get the ratio of 5 decimeters to 4 centimeters, which isn't what the problem's asking for. It wants to know their relative distances, so you need to change 5 decimeters into the equivalent number of centimeters, using the following equation: \[x centimeters = 10xdecimeters\] Or, in other words, there are 10 centimeters in every decimeter.

OpenStudy (lukebluefive):

Sorry, the equation is actually: \[centimeters = 10x decimeters\] Where x is the number of decimeters

OpenStudy (faman39):

40?

OpenStudy (faman39):

50 /40 1. 25

OpenStudy (lukebluefive):

Close. Leave the bottom number as 4, since it's already in centimeters.

OpenStudy (faman39):

12.5, thank you sooooooooooooooooooooo much!!!!!!!!! your terrifically great!!!!!!!!!!!!!

OpenStudy (lukebluefive):

No problem, just glad it all worked out in the end.

OpenStudy (faman39):

Sorry, for me you had to take too pressure, i am extremely sorry for troubling

OpenStudy (lukebluefive):

It's fine, really.

OpenStudy (faman39):

:) thank you

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