Question

dx/dt = 2
find dy/dt
x= (-pi/3)
y=tanx

Answer 1

so its y=tan (-pi/3) find dy/dt

Answer 2

\[y=\tan(x)\]\[\frac{dy}{dt}=\frac{dy}{dx}\frac{dx}{dt}\]
\[\frac{dy}{dx}=\sec^2(x)\]\[\frac{dx}{dt}=2\]

Answer 3

and so \(\frac{dy}{dt}=2\sec^2(x)\)